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18-2w=4w^2
We move all terms to the left:
18-2w-(4w^2)=0
determiningTheFunctionDomain -4w^2-2w+18=0
a = -4; b = -2; c = +18;
Δ = b2-4ac
Δ = -22-4·(-4)·18
Δ = 292
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{292}=\sqrt{4*73}=\sqrt{4}*\sqrt{73}=2\sqrt{73}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{73}}{2*-4}=\frac{2-2\sqrt{73}}{-8} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{73}}{2*-4}=\frac{2+2\sqrt{73}}{-8} $
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