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12x+7=(x+2)4+2x+5
We move all terms to the left:
12x+7-((x+2)4+2x+5)=0
We calculate terms in parentheses: -((x+2)4+2x+5), so:We get rid of parentheses
(x+2)4+2x+5
We add all the numbers together, and all the variables
2x+(x+2)4+5
We multiply parentheses
2x+4x+8+5
We add all the numbers together, and all the variables
6x+13
Back to the equation:
-(6x+13)
12x-6x-13+7=0
We add all the numbers together, and all the variables
6x-6=0
We move all terms containing x to the left, all other terms to the right
6x=6
x=6/6
x=1
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