3(x-5)=7(4+x)-7

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Solution for 3(x-5)=7(4+x)-7 equation: 



3(x-5)=7(4+x)-7

We move all terms to the left:

3(x-5)-(7(4+x)-7)=0

We add all the numbers together, and all the variables

3(x-5)-(7(x+4)-7)=0

We multiply parentheses

3x-(7(x+4)-7)-15=0



We calculate terms in parentheses: -(7(x+4)-7), so:

7(x+4)-7

We multiply parentheses

7x+28-7

We add all the numbers together, and all the variables

7x+21

Back to the equation:

-(7x+21)



We get rid of parentheses

3x-7x-21-15=0

We add all the numbers together, and all the variables

-4x-36=0

We move all terms containing x to the left, all other terms to the right

-4x=36

x=36/-4

x=-9

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