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12x+6=3(2x+1)+6x+3
We move all terms to the left:
12x+6-(3(2x+1)+6x+3)=0
We calculate terms in parentheses: -(3(2x+1)+6x+3), so:We get rid of parentheses
3(2x+1)+6x+3
We add all the numbers together, and all the variables
6x+3(2x+1)+3
We multiply parentheses
6x+6x+3+3
We add all the numbers together, and all the variables
12x+6
Back to the equation:
-(12x+6)
12x-12x-6+6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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