-4(2t-3)+6t=7t-7

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Solution for -4(2t-3)+6t=7t-7 equation: 



-4(2t-3)+6t=7t-7

We move all terms to the left:

-4(2t-3)+6t-(7t-7)=0

We add all the numbers together, and all the variables

6t-4(2t-3)-(7t-7)=0

We multiply parentheses

6t-8t-(7t-7)+12=0

We get rid of parentheses

6t-8t-7t+7+12=0

We add all the numbers together, and all the variables

-9t+19=0

We move all terms containing t to the left, all other terms to the right

-9t=-19

t=-19/-9

t=2+1/9

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