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12x+3=4x^2x+9+4x
We move all terms to the left:
12x+3-(4x^2x+9+4x)=0
We get rid of parentheses
-4x^2x+12x-4x-9+3=0
We add all the numbers together, and all the variables
-4x^2x+8x-6=0
We move all terms containing x to the left, all other terms to the right
-4x^2x+8x=6
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