12x+33=2(11x+79)

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Solution for 12x+33=2(11x+79) equation: 



12x+33=2(11x+79)

We move all terms to the left:

12x+33-(2(11x+79))=0



We calculate terms in parentheses: -(2(11x+79)), so:

2(11x+79)

We multiply parentheses

22x+158

Back to the equation:

-(22x+158)



We get rid of parentheses

12x-22x-158+33=0

We add all the numbers together, and all the variables

-10x-125=0

We move all terms containing x to the left, all other terms to the right

-10x=125

x=125/-10

x=-12+1/2

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