4h(-7+3h)=)

Solution for 4h(-7+3h)=) equation:

4h(-7+3h)=)

We move all terms to the left:

4h(-7+3h)-())=0

We add all the numbers together, and all the variables

4h(3h-7)-())=0

We add all the numbers together, and all the variables

4h(3h-7)=0

We multiply parentheses

12h^2-28h=0

a = 12; b = -28; c = 0;
Δ = b2-4ac
Δ = -282-4·12·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-28}{2*12}=\frac{0}{24}
=0
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+28}{2*12}=\frac{56}{24}
=2+1/3
$