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12x+2(2x-3)=6x+5(5x-1)
We move all terms to the left:
12x+2(2x-3)-(6x+5(5x-1))=0
We multiply parentheses
12x+4x-(6x+5(5x-1))-6=0
We calculate terms in parentheses: -(6x+5(5x-1)), so:We add all the numbers together, and all the variables
6x+5(5x-1)
We multiply parentheses
6x+25x-5
We add all the numbers together, and all the variables
31x-5
Back to the equation:
-(31x-5)
16x-(31x-5)-6=0
We get rid of parentheses
16x-31x+5-6=0
We add all the numbers together, and all the variables
-15x-1=0
We move all terms containing x to the left, all other terms to the right
-15x=1
x=1/-15
x=-1/15
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