5(2x+9)+2(x+11)=3(3x+4)+48

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Solution for 5(2x+9)+2(x+11)=3(3x+4)+48 equation: 



5(2x+9)+2(x+11)=3(3x+4)+48

We move all terms to the left:

5(2x+9)+2(x+11)-(3(3x+4)+48)=0

We multiply parentheses

10x+2x-(3(3x+4)+48)+45+22=0



We calculate terms in parentheses: -(3(3x+4)+48), so:

3(3x+4)+48

We multiply parentheses

9x+12+48

We add all the numbers together, and all the variables

9x+60

Back to the equation:

-(9x+60)



We add all the numbers together, and all the variables

12x-(9x+60)+67=0

We get rid of parentheses

12x-9x-60+67=0

We add all the numbers together, and all the variables

3x+7=0

We move all terms containing x to the left, all other terms to the right

3x=-7

x=-7/3

x=-2+1/3

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