12p2+9p-30=-10

Solution for 12p2+9p-30=-10 equation:

12p^2+9p-30=-10

We move all terms to the left:

12p^2+9p-30-(-10)=0

We add all the numbers together, and all the variables

12p^2+9p-20=0

a = 12; b = 9; c = -20;
Δ = b2-4ac
Δ = 92-4·12·(-20)
Δ = 1041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{1041}}{2*12}=\frac{-9-\sqrt{1041}}{24}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{1041}}{2*12}=\frac{-9+\sqrt{1041}}{24}
$