32=7(y-16)+5y

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Solution for 32=7(y-16)+5y equation: 



32=7(y-16)+5y

We move all terms to the left:

32-(7(y-16)+5y)=0



We calculate terms in parentheses: -(7(y-16)+5y), so:

7(y-16)+5y

We add all the numbers together, and all the variables

5y+7(y-16)

We multiply parentheses

5y+7y-112

We add all the numbers together, and all the variables

12y-112

Back to the equation:

-(12y-112)



We get rid of parentheses

-12y+112+32=0

We add all the numbers together, and all the variables

-12y+144=0

We move all terms containing y to the left, all other terms to the right

-12y=-144

y=-144/-12

y=+12

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