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12m-7m^2+64=0
a = -7; b = 12; c = +64;
Δ = b2-4ac
Δ = 122-4·(-7)·64
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-44}{2*-7}=\frac{-56}{-14} =+4 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+44}{2*-7}=\frac{32}{-14} =-2+2/7 $
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