(a+4)/5-a/7=(a+7)/5

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Solution for (a+4)/5-a/7=(a+7)/5 equation: 



(a+4)/5-a/7=(a+7)/5

We move all terms to the left:

(a+4)/5-a/7-((a+7)/5)=0

We calculate fractions


(-125a^2)/()+(7a+28)/()+(-((a+7)*7)/()=0



We calculate terms in parentheses: +(-((a+7)*7)/(), so:

-((a+7)*7)/(

We multiply all the terms by the denominator


-((a+7)*7)



We calculate terms in parentheses: -((a+7)*7), so:

(a+7)*7

We multiply parentheses

7a+49

Back to the equation:

-(7a+49)



We get rid of parentheses

-7a-49

Back to the equation:

+(-7a-49)



We get rid of parentheses

(-125a^2)/()+(7a+28)/()-7a-49=0

We multiply all the terms by the denominator


(-125a^2)+(7a+28)-7a*()-49*()=0

We add all the numbers together, and all the variables

(-125a^2)+(7a+28)-7a*()=0

We get rid of parentheses

-125a^2+7a-7a*()+28=0

We move all terms containing a to the left, all other terms to the right

-125a^2+7a-7a*()=-28

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