12m(m-2)=0

Solution for 12m(m-2)=0 equation:

12m(m-2)=0

We multiply parentheses

12m^2-24m=0

a = 12; b = -24; c = 0;
Δ = b2-4ac
Δ = -242-4·12·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24}{2*12}=\frac{0}{24}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24}{2*12}=\frac{48}{24}
=2
$