28=-3(21-x)+2(x-2)

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Solution for 28=-3(21-x)+2(x-2) equation: 



28=-3(21-x)+2(x-2)

We move all terms to the left:

28-(-3(21-x)+2(x-2))=0

We add all the numbers together, and all the variables

-(-3(-1x+21)+2(x-2))+28=0



We calculate terms in parentheses: -(-3(-1x+21)+2(x-2)), so:

-3(-1x+21)+2(x-2)

We multiply parentheses

3x+2x-63-4

We add all the numbers together, and all the variables

5x-67

Back to the equation:

-(5x-67)



We get rid of parentheses

-5x+67+28=0

We add all the numbers together, and all the variables

-5x+95=0

We move all terms containing x to the left, all other terms to the right

-5x=-95

x=-95/-5

x=+19

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