12m(m+3)=7m-15

Solution for 12m(m+3)=7m-15 equation:

12m(m+3)=7m-15

We move all terms to the left:

12m(m+3)-(7m-15)=0

We multiply parentheses

12m^2+36m-(7m-15)=0

We get rid of parentheses

12m^2+36m-7m+15=0

We add all the numbers together, and all the variables

12m^2+29m+15=0

a = 12; b = 29; c = +15;
Δ = b2-4ac
Δ = 292-4·12·15
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-11}{2*12}=\frac{-40}{24}
=-1+2/3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+11}{2*12}=\frac{-18}{24}
=-3/4
$