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(1)/(4)(5-2h)=(h)/(2)
We move all terms to the left:
(1)/(4)(5-2h)-((h)/(2))=0
Domain of the equation: 4(5-2h)!=0We add all the numbers together, and all the variables
h∈R
1/4(-2h+5)-(+h/2)=0
We get rid of parentheses
1/4(-2h+5)-h/2=0
We calculate fractions
There is no solution for this equation
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