6(x-2)=3x+1-3(-3x-1)

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Solution for 6(x-2)=3x+1-3(-3x-1) equation: 



6(x-2)=3x+1-3(-3x-1)

We move all terms to the left:

6(x-2)-(3x+1-3(-3x-1))=0

We multiply parentheses

6x-(3x+1-3(-3x-1))-12=0



We calculate terms in parentheses: -(3x+1-3(-3x-1)), so:

3x+1-3(-3x-1)

determiningTheFunctionDomain
3x-3(-3x-1)+1

We multiply parentheses

3x+9x+3+1

We add all the numbers together, and all the variables

12x+4

Back to the equation:

-(12x+4)



We get rid of parentheses

6x-12x-4-12=0

We add all the numbers together, and all the variables

-6x-16=0

We move all terms containing x to the left, all other terms to the right

-6x=16

x=16/-6

x=-2+2/3

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