12j+15=(-20)+10j

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Solution for 12j+15=(-20)+10j equation: 



12j+15=(-20)+10j

We move all terms to the left:

12j+15-((-20)+10j)=0



We calculate terms in parentheses: -((-20)+10j), so:

(-20)+10j

determiningTheFunctionDomain
10j+(-20)

We add all the numbers together, and all the variables

10j-20

Back to the equation:

-(10j-20)



We get rid of parentheses

12j-10j+20+15=0

We add all the numbers together, and all the variables

2j+35=0

We move all terms containing j to the left, all other terms to the right

2j=-35

j=-35/2

j=-17+1/2

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