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(4x+7)(2x+3)=0
We multiply parentheses ..
(+8x^2+12x+14x+21)=0
We get rid of parentheses
8x^2+12x+14x+21=0
We add all the numbers together, and all the variables
8x^2+26x+21=0
a = 8; b = 26; c = +21;
Δ = b2-4ac
Δ = 262-4·8·21
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-2}{2*8}=\frac{-28}{16} =-1+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+2}{2*8}=\frac{-24}{16} =-1+1/2 $
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