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12g=2/3g-1)+11
We move all terms to the left:
12g-(2/3g-1)+11)=0
Domain of the equation: 3g-1)!=0We add all the numbers together, and all the variables
g∈R
12g-(2/3g-1)=0
We get rid of parentheses
12g-2/3g+1=0
We multiply all the terms by the denominator
12g*3g+1*3g-2=0
Wy multiply elements
36g^2+3g-2=0
a = 36; b = 3; c = -2;
Δ = b2-4ac
Δ = 32-4·36·(-2)
Δ = 297
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{297}=\sqrt{9*33}=\sqrt{9}*\sqrt{33}=3\sqrt{33}$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3\sqrt{33}}{2*36}=\frac{-3-3\sqrt{33}}{72} $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3\sqrt{33}}{2*36}=\frac{-3+3\sqrt{33}}{72} $
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