5y+2(3y-1)=y-(y+2

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Solution for 5y+2(3y-1)=y-(y+2 equation: 



5y+2(3y-1)=y-(y+2

We move all terms to the left:

5y+2(3y-1)-(y-(y+2)=0

We multiply parentheses

5y+6y-(y-(y+2)-2=0

We add all the numbers together, and all the variables

11y-(y-(y+2)-2=0

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