12c-30=5(2c+28)

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Solution for 12c-30=5(2c+28) equation: 



12c-30=5(2c+28)

We move all terms to the left:

12c-30-(5(2c+28))=0



We calculate terms in parentheses: -(5(2c+28)), so:

5(2c+28)

We multiply parentheses

10c+140

Back to the equation:

-(10c+140)



We get rid of parentheses

12c-10c-140-30=0

We add all the numbers together, and all the variables

2c-170=0

We move all terms containing c to the left, all other terms to the right

2c=170

c=170/2

c=85

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