-4(p+2)+8=2(p-1)-7p/15

Solution for -4(p+2)+8=2(p-1)-7p/15 equation:

-4(p+2)+8=2(p-1)-7p/15

We move all terms to the left:

-4(p+2)+8-(2(p-1)-7p/15)=0

We multiply parentheses

-4p-(2(p-1)-7p/15)-8+8=0

We multiply all the terms by the denominator


-4p*15)-(2(p-1)-7p-8*15)+8*15)=0

We add all the numbers together, and all the variables

-7p-4p*15)-(2(p-1)=0

Wy multiply elements

-60p^2-7p=0

a = -60; b = -7; c = 0;
Δ = b2-4ac
Δ = -72-4·(-60)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-7}{2*-60}=\frac{0}{-120}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+7}{2*-60}=\frac{14}{-120}
=-7/60
$