12c+30=2(c-5)

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Solution for 12c+30=2(c-5) equation: 



12c+30=2(c-5)

We move all terms to the left:

12c+30-(2(c-5))=0



We calculate terms in parentheses: -(2(c-5)), so:

2(c-5)

We multiply parentheses

2c-10

Back to the equation:

-(2c-10)



We get rid of parentheses

12c-2c+10+30=0

We add all the numbers together, and all the variables

10c+40=0

We move all terms containing c to the left, all other terms to the right

10c=-40

c=-40/10

c=-4

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