4(80+k)=(3k)0

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Solution for 4(80+k)=(3k)0 equation: 



4(80+k)=(3k)0

We move all terms to the left:

4(80+k)-((3k)0)=0

determiningTheFunctionDomain
4(80+k)-3k0=0

We add all the numbers together, and all the variables

4(k+80)-3k0=0

We add all the numbers together, and all the variables

-3k+4(k+80)=0

We multiply parentheses

-3k+4k+320=0

We add all the numbers together, and all the variables

k+320=0

We move all terms containing k to the left, all other terms to the right

k=-320

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