12b2-27=0

Solution for 12b2-27=0 equation:

12b^2-27=0

a = 12; b = 0; c = -27;
Δ = b2-4ac
Δ = 02-4·12·(-27)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36}{2*12}=\frac{-36}{24}
=-1+1/2
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36}{2*12}=\frac{36}{24}
=1+1/2
$