15(x+1)+3x=6-(4x-3)

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Solution for 15(x+1)+3x=6-(4x-3) equation: 



15(x+1)+3x=6-(4x-3)

We move all terms to the left:

15(x+1)+3x-(6-(4x-3))=0

We add all the numbers together, and all the variables

3x+15(x+1)-(6-(4x-3))=0

We multiply parentheses

3x+15x-(6-(4x-3))+15=0



We calculate terms in parentheses: -(6-(4x-3)), so:

6-(4x-3)

determiningTheFunctionDomain
-(4x-3)+6

We get rid of parentheses

-4x+3+6

We add all the numbers together, and all the variables

-4x+9

Back to the equation:

-(-4x+9)



We add all the numbers together, and all the variables

18x-(-4x+9)+15=0

We get rid of parentheses

18x+4x-9+15=0

We add all the numbers together, and all the variables

22x+6=0

We move all terms containing x to the left, all other terms to the right

22x=-6

x=-6/22

x=-3/11

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