12a-4(5a-1)=2(3a-6)+4a

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Solution for 12a-4(5a-1)=2(3a-6)+4a equation: 



12a-4(5a-1)=2(3a-6)+4a

We move all terms to the left:

12a-4(5a-1)-(2(3a-6)+4a)=0

We multiply parentheses

12a-20a-(2(3a-6)+4a)+4=0



We calculate terms in parentheses: -(2(3a-6)+4a), so:

2(3a-6)+4a

We add all the numbers together, and all the variables

4a+2(3a-6)

We multiply parentheses

4a+6a-12

We add all the numbers together, and all the variables

10a-12

Back to the equation:

-(10a-12)



We add all the numbers together, and all the variables

-8a-(10a-12)+4=0

We get rid of parentheses

-8a-10a+12+4=0

We add all the numbers together, and all the variables

-18a+16=0

We move all terms containing a to the left, all other terms to the right

-18a=-16

a=-16/-18

a=8/9

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