4(3c-2)=12(c+12)

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Solution for 4(3c-2)=12(c+12) equation: 



4(3c-2)=12(c+12)

We move all terms to the left:

4(3c-2)-(12(c+12))=0

We multiply parentheses

12c-(12(c+12))-8=0



We calculate terms in parentheses: -(12(c+12)), so:

12(c+12)

We multiply parentheses

12c+144

Back to the equation:

-(12c+144)



We get rid of parentheses

12c-12c-144-8=0

We add all the numbers together, and all the variables

-152!=0

There is no solution for this equation

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