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12=j/3j=
We move all terms to the left:
12-(j/3j)=0
Domain of the equation: 3j)!=0We add all the numbers together, and all the variables
j!=0/1
j!=0
j∈R
-(+j/3j)+12=0
We get rid of parentheses
-j/3j+12=0
We multiply all the terms by the denominator
-j+12*3j=0
We add all the numbers together, and all the variables
-1j+12*3j=0
Wy multiply elements
-1j+36j=0
We add all the numbers together, and all the variables
35j=0
j=0/35
j=0
Równanie nie ma rozwiązania
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