4(x+1)+x=3(x-2)+16

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Solution for 4(x+1)+x=3(x-2)+16 equation: 



4(x+1)+x=3(x-2)+16

We move all terms to the left:

4(x+1)+x-(3(x-2)+16)=0

We add all the numbers together, and all the variables

x+4(x+1)-(3(x-2)+16)=0

We multiply parentheses

x+4x-(3(x-2)+16)+4=0



We calculate terms in parentheses: -(3(x-2)+16), so:

3(x-2)+16

We multiply parentheses

3x-6+16

We add all the numbers together, and all the variables

3x+10

Back to the equation:

-(3x+10)



We add all the numbers together, and all the variables

5x-(3x+10)+4=0

We get rid of parentheses

5x-3x-10+4=0

We add all the numbers together, and all the variables

2x-6=0

We move all terms containing x to the left, all other terms to the right

2x=6

x=6/2

x=3

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