12=4+2(1+j)

Solution for 12=4+2(1+j) equation:

12=4+2(1+j)

We move all terms to the left:

12-(4+2(1+j))=0

We add all the numbers together, and all the variables

-(4+2(j+1))+12=0


We calculate terms in parentheses: -(4+2(j+1)), so:

4+2(j+1)

determiningTheFunctionDomain
2(j+1)+4

We multiply parentheses

2j+2+4

We add all the numbers together, and all the variables

2j+6

Back to the equation:

-(2j+6)


We get rid of parentheses

-2j-6+12=0

We add all the numbers together, and all the variables

-2j+6=0

We move all terms containing j to the left, all other terms to the right

-2j=-6

j=-6/-2

j=+3