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12=2x(6x-6)
We move all terms to the left:
12-(2x(6x-6))=0
We calculate terms in parentheses: -(2x(6x-6)), so:We get rid of parentheses
2x(6x-6)
We multiply parentheses
12x^2-12x
Back to the equation:
-(12x^2-12x)
-12x^2+12x+12=0
a = -12; b = 12; c = +12;
Δ = b2-4ac
Δ = 122-4·(-12)·12
Δ = 720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{720}=\sqrt{144*5}=\sqrt{144}*\sqrt{5}=12\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12\sqrt{5}}{2*-12}=\frac{-12-12\sqrt{5}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12\sqrt{5}}{2*-12}=\frac{-12+12\sqrt{5}}{-24} $
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