12b-12(3b+5)=-4(1-b)

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Solution for 12b-12(3b+5)=-4(1-b) equation: 



12b-12(3b+5)=-4(1-b)

We move all terms to the left:

12b-12(3b+5)-(-4(1-b))=0

We add all the numbers together, and all the variables

12b-12(3b+5)-(-4(-1b+1))=0

We multiply parentheses

12b-36b-(-4(-1b+1))-60=0



We calculate terms in parentheses: -(-4(-1b+1)), so:

-4(-1b+1)

We multiply parentheses

4b-4

Back to the equation:

-(4b-4)



We add all the numbers together, and all the variables

-24b-(4b-4)-60=0

We get rid of parentheses

-24b-4b+4-60=0

We add all the numbers together, and all the variables

-28b-56=0

We move all terms containing b to the left, all other terms to the right

-28b=56

b=56/-28

b=-2

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