12=2(y-4)+3y

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Solution for 12=2(y-4)+3y equation: 



12=2(y-4)+3y

We move all terms to the left:

12-(2(y-4)+3y)=0



We calculate terms in parentheses: -(2(y-4)+3y), so:

2(y-4)+3y

We add all the numbers together, and all the variables

3y+2(y-4)

We multiply parentheses

3y+2y-8

We add all the numbers together, and all the variables

5y-8

Back to the equation:

-(5y-8)



We get rid of parentheses

-5y+8+12=0

We add all the numbers together, and all the variables

-5y+20=0

We move all terms containing y to the left, all other terms to the right

-5y=-20

y=-20/-5

y=+4

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