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-3(5y-1)+9y=1+2(3y-8)
We move all terms to the left:
-3(5y-1)+9y-(1+2(3y-8))=0
We add all the numbers together, and all the variables
9y-3(5y-1)-(1+2(3y-8))=0
We multiply parentheses
9y-15y-(1+2(3y-8))+3=0
We calculate terms in parentheses: -(1+2(3y-8)), so:We add all the numbers together, and all the variables
1+2(3y-8)
determiningTheFunctionDomain 2(3y-8)+1
We multiply parentheses
6y-16+1
We add all the numbers together, and all the variables
6y-15
Back to the equation:
-(6y-15)
-6y-(6y-15)+3=0
We get rid of parentheses
-6y-6y+15+3=0
We add all the numbers together, and all the variables
-12y+18=0
We move all terms containing y to the left, all other terms to the right
-12y=-18
y=-18/-12
y=1+1/2
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