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12=12x-3x^2
We move all terms to the left:
12-(12x-3x^2)=0
We get rid of parentheses
3x^2-12x+12=0
a = 3; b = -12; c = +12;
Δ = b2-4ac
Δ = -122-4·3·12
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{12}{6}=2$
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