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5x^2-32x+48=0
a = 5; b = -32; c = +48;
Δ = b2-4ac
Δ = -322-4·5·48
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-8}{2*5}=\frac{24}{10} =2+2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+8}{2*5}=\frac{40}{10} =4 $
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