12=-10(6+p)2

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Solution for 12=-10(6+p)2 equation: 



12=-10(6+p)2

We move all terms to the left:

12-(-10(6+p)2)=0

We add all the numbers together, and all the variables

-(-10(p+6)2)+12=0



We calculate terms in parentheses: -(-10(p+6)2), so:

-10(p+6)2

We multiply parentheses

-20p-120

Back to the equation:

-(-20p-120)



We get rid of parentheses

20p+120+12=0

We add all the numbers together, and all the variables

20p+132=0

We move all terms containing p to the left, all other terms to the right

20p=-132

p=-132/20

p=-6+3/5

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