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1/2x-2=2-2/4x
We move all terms to the left:
1/2x-2-(2-2/4x)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 4x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/2x-(-2/4x+2)-2=0
We get rid of parentheses
1/2x+2/4x-2-2=0
We calculate fractions
4x/8x^2+4x/8x^2-2-2=0
We add all the numbers together, and all the variables
4x/8x^2+4x/8x^2-4=0
We multiply all the terms by the denominator
4x+4x-4*8x^2=0
We add all the numbers together, and all the variables
8x-4*8x^2=0
Wy multiply elements
-32x^2+8x=0
a = -32; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·(-32)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*-32}=\frac{-16}{-64} =1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*-32}=\frac{0}{-64} =0 $
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