12=(z-1/5)

Solution for 12=(z-1/5) equation:

12=(z-1/5)

We move all terms to the left:

12-((z-1/5))=0

We add all the numbers together, and all the variables

-((+z-1/5))+12=0

We multiply all the terms by the denominator


-((+z-1+12*5))=0


We calculate terms in parentheses: -((+z-1+12*5)), so:

(+z-1+12*5)

We add all the numbers together, and all the variables

(z+59)

We get rid of parentheses

z+59

Back to the equation:

-(z+59)


We get rid of parentheses

-z-59=0

We add all the numbers together, and all the variables

-1z-59=0

We move all terms containing z to the left, all other terms to the right

-z=59

z=59/-1

z=-59