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12=(3x/2x+1)
We move all terms to the left:
12-((3x/2x+1))=0
Domain of the equation: 2x+1))!=0We multiply all the terms by the denominator
x∈R
-((3x+12*2x+1))=0
We calculate terms in parentheses: -((3x+12*2x+1)), so:We get rid of parentheses
(3x+12*2x+1)
We get rid of parentheses
3x+12*2x+1
Wy multiply elements
3x+24x+1
We add all the numbers together, and all the variables
27x+1
Back to the equation:
-(27x+1)
-27x-1=0
We move all terms containing x to the left, all other terms to the right
-27x=1
x=1/-27
x=-1/27
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