12=(3b-5)

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Solution for 12=(3b-5) equation: 



12=(3b-5)

We move all terms to the left:

12-((3b-5))=0



We calculate terms in parentheses: -((3b-5)), so:

(3b-5)

We get rid of parentheses

3b-5

Back to the equation:

-(3b-5)



We get rid of parentheses

-3b+5+12=0

We add all the numbers together, and all the variables

-3b+17=0

We move all terms containing b to the left, all other terms to the right

-3b=-17

b=-17/-3

b=5+2/3

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