3(3x-2)=2(2x+17

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Solution for 3(3x-2)=2(2x+17 equation: 



3(3x-2)=2(2x+17

We move all terms to the left:

3(3x-2)-(2(2x+17)=0

We multiply parentheses

9x-(2(2x+17)-6=0

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