128=-4(7a+3)

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Solution for 128=-4(7a+3) equation: 



128=-4(7a+3)

We move all terms to the left:

128-(-4(7a+3))=0



We calculate terms in parentheses: -(-4(7a+3)), so:

-4(7a+3)

We multiply parentheses

-28a-12

Back to the equation:

-(-28a-12)



We get rid of parentheses

28a+12+128=0

We add all the numbers together, and all the variables

28a+140=0

We move all terms containing a to the left, all other terms to the right

28a=-140

a=-140/28

a=-5

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