12x-8=2(3x-7)+6x+6

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Solution for 12x-8=2(3x-7)+6x+6 equation: 



12x-8=2(3x-7)+6x+6

We move all terms to the left:

12x-8-(2(3x-7)+6x+6)=0



We calculate terms in parentheses: -(2(3x-7)+6x+6), so:

2(3x-7)+6x+6

We add all the numbers together, and all the variables

6x+2(3x-7)+6

We multiply parentheses

6x+6x-14+6

We add all the numbers together, and all the variables

12x-8

Back to the equation:

-(12x-8)



We get rid of parentheses

12x-12x+8-8=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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