125/(x+2)+36=41

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Solution for 125/(x+2)+36=41 equation: 



125/(x+2)+36=41

We move all terms to the left:

125/(x+2)+36-(41)=0



Domain of the equation: (x+2)!=0

We move all terms containing x to the left, all other terms to the right

x!=-2

x∈R



We add all the numbers together, and all the variables

125/(x+2)-5=0

We multiply all the terms by the denominator


-5*(x+2)+125=0

We multiply parentheses

-5x-10+125=0

We add all the numbers together, and all the variables

-5x+115=0

We move all terms containing x to the left, all other terms to the right

-5x=-115

x=-115/-5

x=+23

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