122x+11=6(4x+12)

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Solution for 122x+11=6(4x+12) equation: 



122x+11=6(4x+12)

We move all terms to the left:

122x+11-(6(4x+12))=0



We calculate terms in parentheses: -(6(4x+12)), so:

6(4x+12)

We multiply parentheses

24x+72

Back to the equation:

-(24x+72)



We get rid of parentheses

122x-24x-72+11=0

We add all the numbers together, and all the variables

98x-61=0

We move all terms containing x to the left, all other terms to the right

98x=61

x=61/98

x=61/98

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